If n 2 return 1
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If n 2 return 1
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WebExplanation: The recurrence relation is given by fibo(n) = fibo(n – 1) + fibo(n – 2). So, the time complexity is given by: T(n) = T(n – 1) + T(n – 2) Approximately, T(n) = 2 * T(n – 1) = 4 * T(n – 2) = 8 * T(n – 3)::: = 2 k * T(n – k) This recurrence will stop when n – k = 0 i.e. n = k Therefore, T(n) = 2 n * O(0) = 2 n Web29 jun. 2024 · int DoSomething (int n) { if (n<=2) return 1; else return (DoSomething (floor (sqrt ( n) )) + n); } Options are:- O (n^2) O (n log n) //all logs are with base 2 O (log n ) O …
Webpublic static double H (int N) { if (N == 1) return 1.0; return H (N) + 1.0/N; } Quá tốn bộ nhớ. Mỗi lời gọi hàm cần được lưu lại dấu vết trong bộ nhớ (ngăn xếp các lời gọi hàm - function call stack), các lời gọi hàm đệ quy không phải ngoại lệ. Web5 jun. 2012 · function fibonacci(int n): if n == 0 or n == 1: #for any n less than 2 return 1 elif n >= 2: #for any n 2 or greater return fibonacci(n-1) + fibonacci(n-2) else: #this must n < …
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